qesustion

A pile of 0.5m diameter of length 10m is embedded in deposit of clay. The in- drained strength parameters of clay are cohesion =60KN/m2 and angle of internal friction =0. The skin friction capacity (kN) of pile for an adhesion factor of 0.6, is _?

1. 671
2. 565
3. 283
4. 106

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👆🏾👆🏾𝕊𝕠𝕝𝕦𝕥𝕚𝕠𝕟 𝕗𝕠𝕣 𝕥𝕙𝕚𝕤 𝕢𝕦𝕖𝕤𝕥𝕚𝕠𝕟 👆🏾

Given

➪ Cohesion (C) = 60KN/M² 

➪ Diameter of the pile(D) = 0.5 meters

➪ angle of internal friction( Φ) = 0

➪ Length of the pile(L) = 10 meters 

➪ Adhesion factor (α) = 0.6 

Required 

Skin friction capacity of pile (q𝑓𝑠)=? 

Solution 

✔︎ Q𝑓𝑠 =  π x C X D x L x α

        👉🏿 π=3.14

Q𝑓𝑠 = 3.14 x 0.6 x 10 x 0.5 x 60

Q𝑓𝑠= 565.2 KN