qesustion

A pile of 0.5m diameter of length 10m is embedded in deposit of clay. The in- drained strength parameters of clay are cohesion =60KN/m2 and angle of internal friction =0. The skin friction capacity (kN) of pile for an adhesion factor of 0.6, is _?

1. 671
2. 565
3. 283
4. 106

#foundationengineering
#soil
#pilefoundation

πŸ‘†πŸΎπŸ‘†πŸΎπ•Šπ• π•π•¦π•₯π•šπ• π•Ÿ 𝕗𝕠𝕣 π•₯π•™π•šπ•€ 𝕒𝕦𝕖𝕀π•₯π•šπ• π•Ÿ πŸ‘†πŸΎ

Given

βžͺ Cohesion (C) = 60KN/MΒ² 
βžͺ Diameter of the pile(D) = 0.5 meters
βžͺ angle of internal friction( Ξ¦) = 0
βžͺ Length of the pile(L) = 10 meters 
βžͺ Adhesion factor (Ξ±) = 0.6 

Required 

Skin friction capacity of pile (q𝑓𝑠)=? 

Solution 

βœ”οΈŽ Q𝑓𝑠 =  Ο€ x C X D x L x Ξ±

        πŸ‘‰πŸΏ Ο€=3.14
Q𝑓𝑠 = 3.14 x 0.6 x 10 x 0.5 x 60

Q𝑓𝑠= 565.2 KN 

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question

Qeustion 1 A pile of 0.5m diameter of length 10m is embedded in deposit of clay. The in- drained strength parameters of clay are cohesion =60KN/m2 and angle of internal friction =0. The skin friction capacity (kN) of pile for an adhesion factor of 0.6, is _? 1. 671 2. 565 3. 283 4. 106 #foundationengineering #soil #pilefoundation  see  answer
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